[reposting at the top level because Illum got the reply link wrong; original posted at 23:03 local (most of an hour ago)]
(+) My answer:
The concatenation of the counts of each type of currency, in descending order of denomination, is (11 + (61 × (95768800100 + 53610070574))). The total number of pieces of currency taken is ((13512589 + 29399375) ÷ 1589332).
To be clear on the interpretation, in case I've gotten part of it wrong:
The concatenation of the banknote denominations, in descending order of dollars, with nines between them, is (107 × 943466550569713). The concatenation of the coin denominations, in descending order of cents, with nines between them, is (113 × 8933710257607).
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Date: 12/17/17 05:57 (UTC)[reposting at the top level because Illum got the reply link wrong; original posted at 23:03 local (most of an hour ago)]
(+) My answer:
The concatenation of the counts of each type of currency, in descending order of denomination, is
(11 + (61 × (95768800100 + 53610070574))).
The total number of pieces of currency taken is
((13512589 + 29399375) ÷ 1589332).
To be clear on the interpretation, in case I've gotten part of it wrong:
The concatenation of the banknote denominations, in descending order of dollars, with nines between them, is
(107 × 943466550569713).
The concatenation of the coin denominations, in descending order of cents, with nines between them, is
(113 × 8933710257607).